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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. 	int a, b, n, sum;
  5. 	scanf("%d%d", &a, &b);
  6. 	a = a + (a % 2);
  7. 	b = b - (b % 2);
  8. 	n = (b - a) / 2 + 1;
  9. 	sum = (a + b) * n / 2;
  10. 	printf("%d", sum);
  11. 	return 0;
  12. }
  13.  
Success #stdin #stdout 0s 5324KB
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https://ideone.com/Aclm8R
ZeroJudge d490. 我也愛偶數
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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