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  1. program k_do_n_tej;
  2. var i,k,n,y: integer;
  3.  
  4. begin
  5.     read(k, n);
  6.     write(k,'^',n,'=');
  7. 	y := 1;
  8. 	for i := 1 to n do
  9. 		y := y * k;
  10.     writeln(y);
  11. end.
Success #stdin #stdout 0s 5296KB
comments (?)
stdin
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2 5
stdout
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2^5=32
https://ideone.com/F1QOp0
k ^ n
language:
Pascal (fpc 3.0.4)
created:
23 hours ago
visibility:
public

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