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  1. #include <stdio.h>
  2. #include <stdlib.h>
  3. int main(void) 
  4. {
  5. 	int a,b;
  6. 	char oper;
  7. 	scanf("%d %c %d",&a,&oper,&b);
  8. 	printf("請輸入運算式:");
  9.  
  10. 	switch(oper)
  11. 	{
  12. 	   case '+':
  13. 	      printf("%d+%d=%d\n",a,b,a+b);
  14. 	      break;
  15. 	   case '-':  
  16. 		  printf("%d-%d=%d\n",a,b,a-b);
  17. 		  break;
  18. 	   case '*':
  19. 	      printf("%d*%d=%d\n",a,b,a*b);
  20. 	      break;
  21. 	   case '/':
  22. 	      printf("%d/%d=%.3f\n",a,b,(float)a/b);
  23. 	      break;
  24. 	   default:
  25. 	      printf("這三小");
  26. 	}
  27. 	return 0;
  28. }
  29.  
Success #stdin #stdout 0.01s 5276KB
comments (?)
stdin
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87/85
stdout
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請輸入運算式:87/85=1.024
https://ideone.com/H04uJ2
switch之加減乘除判斷
language:
C (gcc 8.3)
created:
2 days ago
visibility:
public

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