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  1. program czynniki_pierwsze_m;
  2. var x,k,m: integer;
  3.  
  4. begin
  5.     read(m); x:=m; k:=2;
  6.  
  7.     (* tu wstaw kod rozwiązania wypisując kolejne czynniki pierwsze liczby m  *)
  8.     while x > 1 do
  9.     begin
  10.         if x mod k = 0 then
  11.         begin
  12.             write(k, ' ');
  13.             x := x div k;
  14.         end
  15.         else
  16.             k := k + 1;
  17.     end;
  18. end.
Success #stdin #stdout 0s 5300KB
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https://ideone.com/HOsIin
language:
Pascal (fpc 3.0.4)
created:
18 hours ago
visibility:
public

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