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  1. #include <stdio.h>
  2.  
  3. int main() {
  4. 	int year, jan1, n;
  5. 	scanf ("%d%d%d", &year, &jan1, &n);
  6. 	int leap = 0;
  7. 	if ( year % 400 == 0 || ( year % 4 == 0 && year % 100 != 0 ) )
  8. 		leap = 1;
  9. 	for (int i=0; i<n; i++) {
  10. 		int month, date;
  11. 		scanf ("%d%d", &month, &date);
  12. 		int days =  0;
  13. 		switch (month) {
  14. 			case 1: case 3: case 5: case 7: case 8: case 10:
  15. 				if ( date <= 0 || date > 31 )
  16. 					days = -2;
  17. 				break;
  18. 			case 4: case 6: case 9: case 11:
  19. 				if ( date <= 0 || date > 30 )
  20. 					days = -2;
  21. 				break;
  22. 			case 2:
  23. 				if ( date <= 0 || date > (28+leap) )
  24. 					days = -2;
  25. 				break;
  26. 			default:
  27. 				days = -1;
  28. 				break;
  29. 		}
  30. 		if ( days == 0 ) {
  31. 			days = days + date -1;
  32. 			for (int j=1; j<month; j++) {
  33. 				switch (j) {
  34. 					case 1: case 3: case 5: case 7: case 8: case 10:
  35. 						days += 31;
  36. 						break;
  37. 					case 4: case 6: case 9: case 11:
  38. 						days += 30;
  39. 						break;
  40. 					case 2:
  41. 						(leap)? ( days += 29 ) : ( days += 28 );
  42. 						break;
  43. 					default:
  44. 						break;
  45. 				}
  46. 			}
  47. 			printf ("%d ", (jan1+(days%7))%7);			
  48. 		} else {
  49. 			printf("%d ", days);
  50. 		}
  51. 	}
  52. 	return 0;
  53. }
Success #stdin #stdout 0s 5284KB
comments (?)
stdin
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2012 0
5
11 13
11 14
11 15
13 1
1 200
stdout
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2 3 4 -1 -2
https://ideone.com/MAMuHS
What day is today? : Write a program to determine the day for a given day. We will first be given the year, and the day of January first. Then we will need to determine the day of a set of different dates.
language:
C (gcc 8.3)
created:
7 hours ago
visibility:
public

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