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  1. #include <bits/stdc++.h>
  2. using namespace std;
  3. #define int long long int
  4. #define double long double
  5. #define print(a) for(auto x : a) cout << x << " "; cout << endl
  6. inline int power(int a, int b) {
  7. int x = 1;
  8. while (b) {
  9. if (b & 1) x *= a;
  10. a *= a;
  11. b >>= 1;
  12. }
  13. return x;
  14. }
  15.  
  16.  
  17. const int M = 1000000007;
  18. const int N = 3e5+9;
  19. const int INF = 2e9+1;
  20. const int LINF = 2000000000000000001;
  21.  
  22. //_ ***************************** START Below *******************************
  23.  
  24.  
  25.  
  26.  
  27. vector<int> a;
  28.  
  29. //* Using Sorted set
  30. //* O(nLogn)
  31.  
  32. int consistency1(int n, int x, int y) {
  33. int ans = -LINF;
  34.  
  35. vector<int> prefix(n+1, 0);
  36. for(int i=1; i<=n; i++){
  37. prefix[i] = prefix[i-1] + a[i-1];
  38. }
  39. for(int i=1; i<=y-x; i++){
  40. prefix.push_back(-LINF);
  41. }
  42.  
  43. set<pair<int,int> > st;
  44.  
  45. int size = prefix.size();
  46.  
  47. int s = 0, e = 0;
  48. int l = 0;
  49.  
  50. while(e<size){
  51. st.insert({prefix[e], e});
  52.  
  53. while(e-l+1 > y-x+1){
  54. st.erase({prefix[l], l});
  55. l++;
  56. }
  57.  
  58. if(e-s+1 < y+1){
  59. e++;
  60. }
  61. else{
  62.  
  63. int maxi = (*st.rbegin()).first;
  64.  
  65. ans = max(ans, maxi-prefix[s]);
  66.  
  67. st.erase({prefix[l], l});
  68.  
  69. l++;
  70. s++;
  71. e++;
  72. }
  73. }
  74.  
  75.  
  76. return ans;
  77. }
  78.  
  79.  
  80.  
  81.  
  82.  
  83.  
  84. //* Using deque
  85. //* O(n)
  86.  
  87. int consistency2(int n, int x, int y) {
  88. int ans = -LINF;
  89.  
  90. vector<int> prefix(n+1, 0);
  91. for(int i=1; i<=n; i++){
  92. prefix[i] = prefix[i-1] + a[i-1];
  93. }
  94. for(int i=1; i<=y-x; i++){
  95. prefix.push_back(-LINF);
  96. }
  97.  
  98. deque<int> down;
  99.  
  100. int size = prefix.size();
  101.  
  102. int s = 0, e = 0;
  103. int l = 0;
  104.  
  105. while(e<size){
  106. while(!down.empty() && prefix[down.back()] < prefix[e] ) down.pop_back();
  107. down.push_back(e);
  108.  
  109. while(e-l+1 > y-x+1){
  110. if(down.front() == l) down.pop_front();
  111. l++;
  112. }
  113.  
  114. if(e-s+1 < y+1){
  115. e++;
  116. }
  117. else{
  118.  
  119. int maxi = prefix[down.front()];
  120.  
  121. ans = max(ans, maxi-prefix[s]);
  122.  
  123. if(down.front() == l) down.pop_front();
  124.  
  125. l++;
  126. s++;
  127. e++;
  128. }
  129. }
  130.  
  131.  
  132. return ans;
  133. }
  134.  
  135.  
  136.  
  137.  
  138.  
  139.  
  140.  
  141.  
  142.  
  143.  
  144.  
  145.  
  146.  
  147.  
  148. int practice(int n, int x, int y) {
  149. int ans = 0;
  150.  
  151.  
  152. return ans;
  153. }
  154.  
  155.  
  156.  
  157.  
  158. void solve() {
  159.  
  160. int n, x, y;
  161. cin>>n >> x >> y;
  162.  
  163. a.resize(n);
  164. for(int i=0; i<n; i++) cin >> a[i];
  165.  
  166. cout << consistency1(n, x, y) << " " << consistency2(n, x, y) << endl;
  167.  
  168. // cout << consistency1(n, x, y) << " -> " << practice(n, x, y) << endl;
  169.  
  170.  
  171.  
  172.  
  173.  
  174. }
  175.  
  176.  
  177.  
  178.  
  179.  
  180. int32_t main() {
  181. ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);
  182.  
  183. int t = 1;
  184. while (t--) {
  185. solve();
  186. }
  187.  
  188. return 0;
  189. }
Success #stdin #stdout 0s 5320KB
stdin
10 5 6
-70 17 -37 -57 -20 73 76 54 17 54
stdout
274 274