def longest_common_subsequence(text1, text2):
m, n = len(text1), len(text2)
dp = [[0] * (n + 1) for _ in range(m + 1)]
for i in range(1, m + 1):
for j in range(1, n + 1):
if text1[i - 1] == text2[j - 1]:
dp[i][j] = dp[i - 1][j - 1] + 1
else:
dp[i][j] = max(dp[i - 1][j], dp[i][j - 1])
return dp[m][n]
# 测试数据
text1 = "abcde"
text2 = "ace"
result = longest_common_subsequence(text1, text2)
print(result)
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