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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. 	int a=0,n=0,sum=0;
  5. 	 while(sum<=1000)
  6. 	  {
  7. 	  	a=a+1;
  8. 	  	sum=sum+a;
  9. 	  	n=n+1;
  10. 	  	printf("n=%dの時sum=%d,n,sum");
  11. 	  }
  12. 	  printf("%dの時初めて1000をこえる。",n);
  13. 	return 0;
  14. }
  15.  
Success #stdin #stdout 0s 5320KB
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stdin
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Standard input is empty
stdout
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n=-1135435352の時sum=556380560,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sumn=0の時sum=0,n,sum45の時初めて1000をこえる。
https://ideone.com/d5SPqC
language:
C (gcc 8.3)
created:
11 hours ago
visibility:
public

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