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  1. #include <iostream>
  2. using namespace std;
  3.  
  4. int ft_strcmp(string str1, string str2)
  5. {
  6.     int s = 0;
  7.     bool flag = true;
  8.     int count= 0;
  9.     while(flag)
  10.     {
  11.         if(str1[s] == str2[s]){
  12.            count++;
  13.            s++;
  14.         }
  15.         else
  16.         	break;
  17.  
  18.     }  
  19.     return (count);
  20. }
  21.  
  22. int main()
  23. {
  24.     int n1 = 0, n2 = 0;
  25.     int ar1 = 0, ar2 = 0;
  26.     cin >> n1 >> n2;
  27.     string str[n1];
  28.     int len = n1;
  29.     int i = 0;
  30.     int lol = 0;
  31.     while(n1--)
  32.     {
  33.         cin >> str[i];
  34.         i++;
  35.     }
  36.     while(n2--)
  37.     {
  38.         cin >> ar1 >> ar2;
  39.         lol = ft_strcmp(str[ar1 -1] , str[ar2 -1]);
  40.         cout << lol << endl;
  41.     }
  42. }
  43.     // int num;
  44.     // int n1,n2;
  45.     // cin >> num;
  46.     // int nums[num*2];
  47.     // int i = 0;
  48.     // int max = 0;
  49.     // int min = 0;
  50.     // int first = 1;
  51.     // int count = 0;
  52.     // while(num--)
  53.     // {
  54.     //     cin >> n1 >> n2;
  55.     //     nums[i]=n1;
  56.     //     i++;
  57.     //     nums[i]=n2;
  58.     //     i++;
  59.     //     if(first){
  60.     //         min = n1;
  61.     //         max = n2;
  62.     //         first = 0;
  63.     //     }
  64.     //     if(max < n1)
  65.     //         count += (n1 - max) - 1;
  66.     //     if(min > n2)
  67.     //     {
  68.     //         count += (min - n2) - 1;
  69.     //         max = n2;
  70.     //     }
  71.     //     if(min > n1)
  72.     //         min = n1;
  73.     //     if(max < n2)
  74.     //         max = n2;
  75.  
  76.     // }
  77.     // cout << count;
Success #stdin #stdout 0.01s 5284KB
comments (?)
stdin
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4 5
ababa
aba
abcd
bbbb
1 2
1 3
1 4
2 3
3 4
stdout
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3
2
0
2
0
https://ideone.com/hgZN9R
language:
C++ (gcc 8.3)
created:
15 hours ago
visibility:
public

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