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  1. #include <stdio.h>
  2. #include <string.h>
  3. #include <stdlib.h>
  4.  
  5. int main() {
  6. 	char num[3];
  7. 	char* r = (char*)&num;
  8. 	printf("Enter a 2 digit number such as 23: ");
  9. 	fgets(num, 3, stdin);
  10. 	fflush(stdout);
  11.  
  12. 	if(&num[0] < &num[1]){
  13. 		printf("LITTLE ENDIAN\n");
  14. 	} else{
  15. 		printf("BIG ENDIAN\n");
  16. 	}
  17.  
  18. 	for(int i = 0; i < 2; i++){
  19. 		printf("Address of 0x%x = %u\n", num[i], &num[i]);
  20. 	}
  21.  
  22. 	return 0;
  23. }
  24.  
  25.  
Success #stdin #stdout 0s 5316KB
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stdin
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123
stdout
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Enter a 2 digit number such as 23: LITTLE ENDIAN
Address of 0x31 = 3016429141
Address of 0x32 = 3016429142
https://ideone.com/iY7Q7b
language:
C (gcc 8.3)
created:
2 days ago
visibility:
public

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