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  1. #include <stdio.h>
  2. void call(int x,int y,int *add, int *dif);
  3. int main(void) {
  4. int n1,n2,a,b;
  5. scanf("%d",&n1);
  6. scanf("%d",&n2);
  7. call(n1,n2,&a,&b);
  8. printf("add=%d,dif=%d\n",a,b);
  9. 	return 0;
  10. }
  11. call(int x,int y,int *add, int *dif){
  12. 	*add=x+y;
  13. 	*dif=x-y;
  14. }
  15.  
Success #stdin #stdout 0s 5288KB
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stdin
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2 3
stdout
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add=5,dif=-1
https://ideone.com/rJOoeo
language:
C (gcc 8.3)
created:
11 days ago
visibility:
public

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