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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. int n,count=0;
  5. scanf("%d",&n);
  6. if(n<0){
  7. 	n=-n;
  8. }
  9. do{
  10. 	count++;
  11. 	n=n/10;
  12. }while(n>0);
  13. printf("桁数は%d桁です\n",count);
  14. 	return 0;
  15. }
  16.  
Success #stdin #stdout 0.01s 5316KB
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stdout
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桁数は3桁です
https://ideone.com/rToFWU
language:
C99 (gcc 8.3)
created:
8 hours ago
visibility:
public

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