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  1. #include <stdio.h>
  2.  
  3. int main(void) {
  4. 	int t;
  5. 	scanf("%d", &t);
  6. 	for (int i = 0; i < t; i++) {
  7. 		int year;
  8. 		scanf("%d", &year);
  9. 		if (year % 400 == 0)
  10. 			printf("a leap year\n");
  11. 		else if (year % 4 == 0 && year % 100 != 0)
  12. 			printf("a leap year\n");
  13. 		else
  14. 			printf("a normal year\n");
  15. 	}
  16. 	return 0;
  17. }
  18.  
Success #stdin #stdout 0.01s 5292KB
comments (?)
stdin 
4
1992
1993
1900
2000
stdout 
a leap year
a normal year
a normal year
a leap year
https://ideone.com/xZ8kee
ZeroJudge d069. 格瑞哥里的煩惱 (t 行版)
language:
C (gcc 8.3)
created:
3 days ago
visibility:
public

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